1 a) x² + 5x – 2
b) x³ – 4x – 1
c) x² – 6x + 4
d) x² – 7x + 12



2 a) x₁ = 1 ; x₂ = 2 ; x₃ = 3
b) x₁ = –2 ; x₂ = –1 ; x₃ = 2
c) x₁ = (doppelte Nullstelle) ; x₂ = 1
d) x₁ = (doppelte Nullstelle) ; x₂ = 3
e) x₁ = –2 ; x₂ = ; x₃ =
f) x₁ = –1 ; x₂ = (doppelte Nullstelle)
g) x₁ = –2
h) x₁ = ; x₂ = ; x₃ = 6


3 a) x₁ = 2 ; x₂ = 6
b) x₁ = 1
c) x₁ = 2
d) x₁ = –3 ; x₂ = 0 ; x₃ = 1

4 a) x₁ = , x₂ = 1 ; x₃ =
b) x₁ = 0 ; x₂ = 1 ; x₃ = 4
c) x₁ = –2 ; x₂ = 1



5 a) x·(x+1)·(x–2)
b) –(x–1)·(x–2)·(x+1)
c) –(x–1)·(x+1)·(x–2)·(x+2)
d)


6 a) t = 2 : x₁ = 0
t = 10: x₁ = 0 ; x₂ = 1 ; x₃ = 4
t = –10 : x₁ = –4 ; x₂ = –1 ; x₃ = 0
b) für |t |> 8
c) t = 8


7 a) weil das Dreieck gleichschenklig-rechtwinklig ist, ist h = 10 – r. Dann Volumenformel anwenden.
b) r = 5: V_Kegel = und V_Zylinder = 125
c) r =